Python function is not callable
Here’s a Python gotcha that got me. Here is my function to print out a range of sinusoidal values:
import math
def cycle(centre, range):
theta = 4.71
speed = 0.1
for i in range(0,80):
theta = theta + speed
value = centre + (range * math.sin(theta))
print value
I got the following error which confused the hell out of me:
Traceback (most recent call last): File "cycle2.py", line 11, incycle(0.0,10.0) File "cycle2.py", line 6, in cycle for i in range(0,80): TypeError: 'float' object is not callable
Can you see it? It took me a while. I’d assigned a variable called range and then tried to call the range() function. I’d overloaded a built-in function. Duh!
I just had to rename my variable and it was good.
Have you stopped using a keyword as your variable name?
http://docs.python.org/library/functions.html?highlight=range#range
Ah, thank you. I was doing the same idiot thing with min, and the error message is cryptic (well, unless you see the error – then it makes sense). D’oh!
Anyway, you saved me some time. :)
Haha… I just spend a good 10 minutes trying to figure out the same error, have to be more careful when naming variables. Thanks for your post.